solve the equation sin^4x+cos^4x=sinxcosx
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(sin^2x + cos^2x)(sin^2x - cos^2x) = 7/2(sinxcosx)
1(sin^2x - cos^2x) = 7/2(sinxcosx)
cos^2x - sin^2x = -(7/2)(1/2)(2sinxcosx)
cos 2x = -(7/4)sin 2x
-4/7 = sin2x/cos2x
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