solve the equation sin theeta +cos theeta =root2
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sinΦ + cos Φ = √2
let , Φ = 45°
sin45° + cos45°
1/√2 + 1/√2
2/√2
√2
Proved...
let , Φ = 45°
sin45° + cos45°
1/√2 + 1/√2
2/√2
√2
Proved...
Answered by
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sin∅+cos∅=√2
squaring both sides
sin²∅ +cos²∅ + 2sin∅cos∅= 2
1 + sin2∅ = 2
sin2∅ = 1
2∅= 90
∅= 45°
squaring both sides
sin²∅ +cos²∅ + 2sin∅cos∅= 2
1 + sin2∅ = 2
sin2∅ = 1
2∅= 90
∅= 45°
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