Question

solve the equation sin2x+3cos2x=0

Answer 1

$\huge \underline\red { \mathfrak{solution}} \\ \\ \implies \bf{ \: sin2x + 3cos2x = 0 }\\ \\ \implies \red { \bf{ sin2x = - 3cos2x }}\\ \\ \implies \: \bf{ \frac{sin2x}{cos2x} = - 3 }\\ \\ \implies \: \bf{tan2x = - 3} \\ \\ \implies \: \bf{ \green{ 2x = {tan}^{ - 1} ( - 3)} }\\ \\ \implies \: \bf{ \pink{\boxed{x = \frac{1}{2} {tan}^{ - 1} ( - 3)}}}$

Answer 2

Step-by-step explanation:

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