Solve the equation sin3x+sin5x+sin7x=0, for 90
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Step-by-step explanation:
B =
⇒ -sin 3x + 2 sin
⇒ 2sin 3x cos 2x – sin 3x = 0
⇒ sin 3x ( 2cos 2x – 1) = 0
∴ either, sin 3x = 0 or 2cos 2x – 1 = 0
⇒ sin 3x = sin 0 or cos 2x = � = cos π/3
If sin x = sin y, implies x = nπ + (– 1)ny, where n ∈ Z.
If cos x = cos y, implies x = 2nπ ± y, where
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