Question

solve the equation
$4 \sqrt{3x {}^{2} + 5x - 2 \sqrt{3 = 0} }$

Answer 1

Hope this will help u
$4 \sqrt{6}$

Answer 2

Answer:

The solution of the equation are $x=0.526,-2.193$

Step-by-step explanation:

Given : Equation $4\sqrt{3x^2+5x-2\sqrt3}=0$  

To find : Solve the equation ?

Solution :

$4\sqrt{3x^2+5x-2\sqrt3}=0$  

Divide both side by 4,

$\sqrt{3x^2+5x-2\sqrt3}=0$  

Squaring both side,

$3x^2+5x-2\sqrt3=0$  

Solve by quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here, a=3 , b=5, $c=-2\sqrt3$

$x=\frac{-5\pm\sqrt{5^2-4(3)(-2\sqrt3)}}{2(3)}$

$x=\frac{-5\pm\sqrt{25+24\sqrt3}}{6}$

$x=\frac{-5+\sqrt{25+24\sqrt3}}{6},\frac{-5-\sqrt{25+24\sqrt3}}{6}$

$x=0.526,-2.193$

The solution of the equation are $x=0.526,-2.193$