Question

solve the equation :
$\sqrt{3 {x}^{2} - 2} = 2x - 1$
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Answer 1

Answer:

x=3 or x=1

Step-by-step explanation:

$\sqrt{3x {}^{2} - 2 } = 2x - 1 \\ squaring \: both \: sides \\ 3x {}^{2} - 2 = (2x - 1) {}^{2} \\ x {}^{2} - 3x - x + 3 \\ x(x - 3) - 1(x - 3) \\ x = 1orx = 3$