Solve the equation: ![tan[cos^{-1}(\frac{1}{x})] = sin[cot^{-1}(\frac{1}{2})];\ x \neq 0](https://tex.z-dn.net/?f=+tan%5Bcos%5E%7B-1%7D%28%5Cfrac%7B1%7D%7Bx%7D%29%5D+%3D+sin%5Bcot%5E%7B-1%7D%28%5Cfrac%7B1%7D%7B2%7D%29%5D%3B%5C+x+%5Cneq+0+ "tan[cos^{-1}(\frac{1}{x})] = sin[cot^{-1}(\frac{1}{2})];\ x \neq 0")
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Answer:
The answer to this question is " x = 3/√5 "
Explanation:
This question involves inverse trigonometric functions.
We need to remeber one thing.
Only one-to-one functions have inverse functions.
The Trigonometric Functions are not one-to-one functions.
But we can make them one-to-one functions by restricting their domain.
Kindly see the attachment for detailed answer.
I hope it will help you.
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