Question

solve the equation
$y {}^{2} + \frac{1}{3}y = 2$
y = ????
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Answer 1

Step-by-step explanation:

${y}^{2} + \frac{1}{3} y = 2 \\ {y}^{2} + \frac{1}{3}y - 2 =0 \\ \frac{3 {y}^{2} + y - 2 }{3} = 0 \\ \\ it \: is \: a \:quadratic \: equation \\ \: {3y}^{2} + y - 2 = 0 \\ 3 {y}^{2} + 3y - 2y - 2 = 0 \\ 3y(y + 1) - 2(y + 1) = 0 \\ (3y - 2)(y + 1) = 0 \\ 3y - 2 = 0 ,y + 1 = 0 \\ y = \frac{2}{3} ,y = - 1$