Question

solve the equation to find values of variable in equation -3 (4y-2) + 4 (-3y) =3(y+2)
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Answer 1

Step-by-step explanation:

-12y+6-12y= 3y+6

-24y+6 = 3y+6

27y=O

Hence y= 0

Answer 2

Answer:

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Step-by-step explanation:

→ -3(4y-2) + 4(-3y) = 3(y+2)

→ -3 × 4y + 3 × 2 + (4 × (-3y)) = 3 × y + 3 × 2

→ -12y + 6 +(-12y) = 3y + 6

→ -12y + 6 - 12y  = 3y + 6

→ -12y - 12y + 6 = 3y + 6

→ -24y + 6 = 3y + 6

→ -24y - 3y = 6 - 6

→ -27y = 0

→ y = 0/27

→ y = 0