Solve the equation using logarithm?
5^(x+2) = 7^(x-2)
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5^(x+2)=7^(x-2)
5^x*5^2=7^x/7^2
5^x/7^x=49/25
now
(5/7)^x=49/25
now
if a^x=N
then logto base a(N)=x
so
log base 5/7 (49/25)=x
5^x*5^2=7^x/7^2
5^x/7^x=49/25
now
(5/7)^x=49/25
now
if a^x=N
then logto base a(N)=x
so
log base 5/7 (49/25)=x
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