Question

Solve the equation using logarithm?
5^(x+2) = 7^(x-2)

Answer 1

5^(x+2)=7^(x-2)
5^x*5^2=7^x/7^2
5^x/7^x=49/25
now
(5/7)^x=49/25
now
if a^x=N
then  logto base a(N)=x
so
log base 5/7 (49/25)=x