Question

solve the equation using the quadratic formula
8x²+6x-5=0

Answer 1

$\huge{\fbox{\fbox{\bigstar{\mathfrak{\red{Answer}}}}}}$

$\huge \implies \large \sf \: 8 {x}^{2} + 6x - 5 = 0 \\ \huge \bullet \large \sf \: d = {b}^{2} - 4ac \\ \small \implies \large \sf \: {6}^{2} - 4(8)( - 5) \\ \small \implies \large \sf \: 36 + 32(5) \\ \small \implies \large \sf \: 36 + 160 \\ \small \implies \large \sf \: 196 \\ \huge \implies \large \sf \: x = \frac{{ - b ± \sqrt{d} } }{2a} \\ \small \implies \large \sf \: x = \frac{6 ± \sqrt{196} }{2(8)} \\ \small \implies \large \sf \: \frac{ - 6 + 14}{18} \\ \small \implies \large \sf \: x = \cancel \frac{8}{18} = \: \frac{4}{9} \\ \large \implies \large \sf \: x = \frac{ - 6 - 14}{18} \\ \small \implies \large \sf \: x = \cancel\frac{ - 20}{18} = \frac{ - 10}{9}$

$\huge \implies \large\boxed{\boxed{\underline{\red{\bold{ x=-\frac{10}{9} \:and x=\frac{4}{9} }}}}}$

Answer 2

$\huge{\underline{\tt{SoluTion}}}$

$\huge \implies \large \tt \: 8 {x}^{2} + 6x - 5 = 0 \\ \huge \implies\large \tt \: d = {b}^{2} - 4ac \\ \small \implies \large \tt\: {6}^{2} - 4(8)( - 5) \\ \small \implies \large \tt\: 36 + 32(5) \\ \small \implies \large \tt \: 36 + 160 \\ \small \implies \large \sf \: 196 \\ \huge \implies \large \tt \: x = \frac{{ - b ± \sqrt{d} } }{2a} \\ \small \implies \large \tt\: x = \frac{6 ± \sqrt{196} }{2(8)} \\ \small \implies \large \tt\: \frac{ - 6 + 14}{18} \\ \small \implies \large \tt\: x = \cancel \frac{8}{18} = \: \frac{4}{9} \\ \large \implies \large \tt\: x = \frac{ - 6 - 14}{18} \\ \small \implies \large \tt \: x = \cancel\frac{ - 20}{18} = \frac{ - 10}{9}$