Question

Solve the equation without transposing 5Z=35​

Answer 1

Answer:

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Step-by-step explanation:

Here, we put different values of y in the given equation 5y+10=4y−10.

When x=5,

5y+10=4y−10⟹ 5(5)+10=4(5)−10

⟹ 35



=10.

When x=−5,

5y+10=4y−10⟹ 5(−5)+10=4(−5)−10

⟹ −15



=−30.

When x=10,

5y+10=4y−10⟹ 5(10)+10=4(10)−10

⟹ 60



=30.

When x=−10,

5y+10=4y−10⟹ 5(−10)+10=4(−10)−10

⟹ −40



=−50.

When x=15,

5y+10=4y−10⟹ 5(15)+10=4(15)−10

⟹ 85



=50.

When x=−15,

5y+10=4y−10⟹ 5(−15)+10=4(−15)−10

⟹ −65



=−70.

When x=20,

5y+10=4y−10⟹ 5(20)+10=4(20)−10

⟹ 110



=70.

When x=−20,

5y+10=4y−10⟹ 5(−20)+10=4(−20)−10

⟹ −90=−90.

Therefore, the value of y is −20.

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