Question

solve the equation (x+1)²+x²=221 using the method of factorization​

Answer 1

{(a+b)^2 = a^2 + b^2 + 2ab }

so , x^2 + 1 + 2x + x^2 = 221

=> 2x^2 + 2x - 220 = 0

Here a = 2 , b = 2 , c = -220

=> x = -b+√(b^2 - 4ac)/2a (or) -b-√(b^2 - 4ac)/2a

=> x = 220 + 4√3135 / 4 (or) 220 - 4√3135 / 4