Question

solve the equation (x+1) (2x+1)=(x+3) (2x+3)-14​

Answer 1

$\huge{\pink{\boxed{\boxed{\boxed{\purple{\underline{\underline{\green{\mathfrak{AnSwEr}}}}}}}}}}$

$(x + 1)(2x + 1) = (x + 3)(2x + 3) - 14 \\ x(2x + 1) + 1(2x + 1) = x(2x + 3) + 3(2x + 3) - 14 \\ {2x}^{2} + x + 2x + 1 = {2x}^{2} + 3x + 6x + 9 - 14 \\ {2x}^{2} + 3x + 1 = {2x}^{2} + 9x - 5 \\ {2x}^{2} - {2x}^{2} + 3x - 9x = - 5 - 1 \\ - 6x = - 6 \\ 6x = 6 \\ x = \frac{6}{6} \\ x = 1$

Answer 2

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

(x+1)(2x+1)=(x+3)(2x+3)−14

x(2x+1)+1(2x+1)=x(2x+3)+3(2x+3)−14

2x

2

+x+2x+1=2x

2

+3x+6x+9−14

2x

2

+3x+1=2x

2

+9x−5

2x

2

−2x

2

+3x−9x=−5−1

−6x=−6

6x=6

x=

6

6

x=1

$\huge{\underline{\underline{\mathfrak{Thank You}}}}$