Math, asked by aanchal654, 1 year ago

solve the equation : (x+1)(4x-3)-4x²+5/4x+1=2
plzz

Answers

Answered by Anonymous
19

4x^2 +4x-3x-3 -4x^2 +5/4 x+1 =2


x+5x/4 =4


9x/4 =4


x= 16/9




amit979thakur: Not getting this sum plz explain step by step...
amit979thakur: plz
Answered by pinquancaro
79

Answer:

The solution of the equation is x=0.

Step-by-step explanation:

Given : Equation \frac{(x+1)(4x-3)-4x^2+5}{4x+1}=2

To find : Solve the equation ?

Solution :

\frac{(x+1)(4x-3)-4x^2+5}{4x+1}=2

Cross multiply,

(x+1)(4x-3)-4x^2+5=2(4x+1)

4x^2-3x+4x-3-4x^2+5=8x+2

x+2=8x+2

-7x=0

x=0

Therefore, The solution of the equation is x=0.

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