solve the equation (x-1)power 3+8=0
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−1,1−2ω,1−2
Step-by-step explanation:
I’m assuming that you are aware about cube roots of unity. This question asks us to find the roots in terms of ω.ω. So, rewrite the equation as:
(x−1)3=−8(x−1)3=−8
=>(x−1)3=(−2)3(x−1)3=(−2)3
=> (x−1−2)3=1(x−1−2)3=1
Let t=x−1−2.t=x−1−2. So, t3=1=>t=1,ωt3=1=>t=1,ω or ω2ω2
t=1:t=1:
t=x−1−2=1=>x=−1t=x−1−2=1=>x=−1
t=ω:t=ω:
t=x−1−2=ω=>x=1−2ωt=x−1−2=ω=>x=1−2ω
t=ω2:t=ω2:
t=x−1−2=ω2=>x=1−2ω2t=x−1−2=ω2=>x=1−2ω2
So, the roots are −1,1−2ω,1−2
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