solve the equation (x-1)(x -2)/(x-3)(x-4) > 0
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Answer:
x−1÷x=3
{x }^{2} - 1 = 3xx2−1=3x
{x}^{2} - 3x - 1 = 0x2−3x−1=0
So,
x = (3 + \sqrt{ { ( - 3)}^{2} - 4 \times 1 \times ( - 1)} )\div (2 \times 1)x=(3+(−3)2−4×1×(−1))÷(2×1)
Or
x = (3 - \sqrt{ {( - 3)}^{2} - 4 \times 1 \times ( - 1d)}) \div (2 \times 1)x=(3−(−3)2−4×1×(−1d))÷(2×1)
\begin{gathered}x = (3 + \sqrt{13} ) \div 2 \\ or \\ x = (3 - \sqrt{13}) \div 2 \end{gathered}x=(3+13)÷2orx=(3−13)÷2
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