Math, asked by khushivish932, 5 months ago

solve the equation (x+1upon x-1) -(x-1upon x+1) = 5upon 6​

Answers

Answered by rimpasingharoy654
2

Answer:

 \frac{x + 1}{x - 1}  -  \frac{x - 1}{x + 1}  =  \frac{5}{6}  \\  \frac{ {(x + 1)}^{2} -  {(x - 1)}^{2}  } {(x + 1)(x - 1) }  =  \frac{5}{6}  \\  \frac{4x}{ {x}^{2}  -  {1}^{2} }  =  \frac{5}{6}  \\  24x = 5( {x}^{2}   - 1) \\ 5 {x}^{2}  - 24x - 5 = 0 \\ 5 {x}^{2}  - 25x + x - 5 = 0 \\ (5x + 1)( x - 5) = 0 \\ x =   \frac{ - 1}{5} or5

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