Question

Solve the equation (X-2) ²

Answer 1

Answer:

x^2-4x+4

Step-by-step explanation:

Hope you get this solution.

Answer 2

Correct question is 'Solve the equation (X-2)²= 0'

Answer:

Required value of x is 2.

Step-by-step explanation:

Given,

${(x - 2)}^{2} = 0$

We want to solve the equation.

Now,

${(x - 2)}^{2} = (x - 2)(x - 2)$

So,

$(x - 2)(x - 2) = 0$

If product of two terms are zero then they are separately zero.

So,

$x - 2 = 0 \\ x = 2$

Therefore required value of x is 2.

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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