Question

Solve the equation x^2+2√2x-6=0
By using formula method ​

Answer 1

Answer:

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Step-by-step explanation:

Given quadratic equation :

x²+2v2x-6=0

Splitting the middle term, we get

=> x²+3v2x-v2x-6=0

=> x²+3v2x-v2x-v2x3/2=0

=> x(x+372)-v2(x+372)=0

=> (x+3v2)(x-v2)=0

=> x+372=0 Or x-v2=0

=> x = -3/2 Or x = v2

Therefore,

Roots of given quadratic equation :

x = -3v2 Or x = v2

Answer 2

Answer:

Given quadratic equation :

x²+2v2x-6=0

Splitting the middle term, we get

=> x²+3v2x-v2x-6=0

=> x²+3v2x-v2x-v2x3/2=0

=> x(x+372)-v2(x+372)=0

=> (x+3v2)(x-v2)=0

=> x+372=0 Or x-v2=0

=> x = -3/2 Or x = v2

Therefore,

Roots of given quadratic equation :

x = -3v2 Or x = v2