Question

solve the equation x^2-2x-3=0 by completing the square​

Answer 1

Answer:

(x-3)(x+1)

Step-by-step explanation:

transfer 3 to RHS

ADD -B/2A BOTH SIDES WHICH YOU MUST BE KNOWING

THEN PROCEED AS IN QUADRATIC FORMULA DERIVATION

THANK YOU

for your knowledge it's out of CBSE syllabus

Answer 2

Step-by-step explanation:

x² - 2x - 3 =0

→x² - 2x + 1 - 4 = 0

→(x - 1)² - (2)² = 0 [x² - 2x + 1 = (x - 1)² ]

→(x - 1 - 2)(x - 1 + 2) =0. [a² - b² = (a + b)(a - b)]

→(x - 3)(x + 1) = 0

Either. or

x - 3 = 0. x + 1 = 0

→x = 3. →x = - 1

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