Math, asked by ashokjhaspj185, 10 months ago

solve the equation X/2+X/3+X/4-26=0 by cross multiplication method​

Answers

Answered by mrunmayee02
8

Answer:

x/2 +x/3 + x/4 - 26 =0

(2x + 3x) /6 + x/4 = 26

5x /6 + x/4 =26

(20x + 6x )/ 24 = 26

26x = 26 . 24

x = 26. 24 /26

x = 24

may be this helps you....

Answered by sharmamilan787
2

Answer:

Answer

Step-by-step explanation:

X/2 +X/3+X/4-26 =0

X[1/2+1/3+1/4]-26=0

NOW WE HAVE TO TAKE LCM OF 2,3 AND 4

LCM =12

1/2×6=6/12

1/3×4=4/12

1/4×3=3/12

X[6/12+4/12+3/12]

X[6+4+3/12]-26=0

X=[13/12]-26=0

X=12×26

13

X =24

Similar questions