Question

solve the equation: X/2+y/9=11 & X/3+y/6=9​

Answer 1

Step-by-step explanation:

Step 1 :

X/2+y/9=11

(9X+2y)/18=11

9X+2y=198.......(1)

X/3+y/6=9

(2X+y)/6=9

2X+y=54.......(2)

Step 2:

Now multiply by 2 in equation 2.

4X+2y=108

Step 3:

Now equation 2 substract from equation 1

9X+2y=198

4X+2y=108

-. -. -

5X=90

X=18

Step 4:

Now put the value of X in equation 1

9X+2y=198

9*18+2y=198

162+2y=198

2y=198-162

2y=36

y=18

Step 5:

x=18

x=18y=18

Answer 2

ANSWER:-

Given:

$\frac{x}{2}\:+\:\frac{y}{9}\:=\:11$

&

$\frac{x}{3}\:+\:\frac{y}{6}\:=\:9$

To find:

Solve the equation.

Explanation:

$\frac{x}{2}+\frac{y}{9} =11.......................(1)\\\\\frac{x}{3}+\frac{y}{6}=9.........................(2)$

From equation (1), we get;

Taking L.C.M of the both denominator:

$=>\:\frac{9x+2y}{18} =11\\\\=>\:9x+2y=198\\\\=>\:9x=198-2y\\\\=>\:x=\frac{198-2y}{9} .....................(3)$

&

From equation (2),we get;

Taking the L.C.M of both denominators:

$=>\:\frac{2x+y}{6} =9\\\\=>\:2x+y=54........................(4)$

• Using substitution Method:

Putting the value of x from equation (3) in equation (4),we get;

$=>\:2(\frac{198-2y}{9} )+y=54\\\\=>\:\frac{396-4y}{9} +y=54\\\\=>\:396-4y+9y=486\\\\=>\:396+5y=486\\\\=>\:5y=486\:-\:396\\\\=>\:5y=90\\\\=>\:y=\frac{90}{5} \\\\=>\:y=18$

Now,

Putting the value of y in equation (3),we get;

$=>\:x=\frac{198-2(18)}{9} \\\\=>\:x=\frac{198-36}{9} \\\\=>\:x=\frac{162}{9} \\\\=>\:x=18$

Thus,

The value of x is 18 and y is also 18.