solve the equation x^3-3x^2+4=0,two òf roots being equal
Answers
Answer:
Step-by-step explanation:
Simplifying
0.5(4x + 1) = 0.3(5x + -1) + 1.2
Reorder the terms:
0.5(1 + 4x) = 0.3(5x + -1) + 1.2
(1 * 0.5 + 4x * 0.5) = 0.3(5x + -1) + 1.2
(0.5 + 2x) = 0.3(5x + -1) + 1.2
Reorder the terms:
0.5 + 2x = 0.3(-1 + 5x) + 1.2
0.5 + 2x = (-1 * 0.3 + 5x * 0.3) + 1.2
0.5 + 2x = (-0.3 + 1.5x) + 1.2
Reorder the terms:
0.5 + 2x = -0.3 + 1.2 + 1.5x
Combine like terms: -0.3 + 1.2 = 0.9
0.5 + 2x = 0.9 + 1.5x
Solving
0.5 + 2x = 0.9 + 1.5x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-1.5x' to each side of the equation.
0.5 + 2x + -1.5x = 0.9 + 1.5x + -1.5x
Combine like terms: 2x + -1.5x = 0.5x
0.5 + 0.5x = 0.9 + 1.5x + -1.5x
Combine like terms: 1.5x + -1.5x = 0.0
0.5 + 0.5x = 0.9 + 0.0
0.5 + 0.5x = 0.9
Add '-0.5' to each side of the equation.
0.5 + -0.5 + 0.5x = 0.9 + -0.5
Combine like terms: 0.5 + -0.5 = 0.0
0.0 + 0.5x = 0.9 + -0.5
0.5x = 0.9 + -0.5
Combine like terms: 0.9 + -0.5 = 0.4
0.5x = 0.4
Divide each side by '0.5'.
x = 0.8
Simplifying
x = 0.8