solve the equation|X-3| = X-3
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[0010001111]... Hello User... [1001010101]
Here's your answer...
|x - 3| = x - 3
When the mod will be removed, ± will get added to RHS
x - 3 = ± (x - 3)
For +...
x - 3 = x - 3
Which is pointless, really
For -...
x - 3 = -x + 3
2x = 6
x = 3
[0110100101]... More questions detected... [010110011110]
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Here's your answer...
|x - 3| = x - 3
When the mod will be removed, ± will get added to RHS
x - 3 = ± (x - 3)
For +...
x - 3 = x - 3
Which is pointless, really
For -...
x - 3 = -x + 3
2x = 6
x = 3
[0110100101]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
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