solve the equation x/3+y/2=4, 2x/3-y/4=3
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Answered by
1
ANSWER
2x+3y=14,2x−3y=2
Adding :
2x+3y=14
2x−3y=2
__________
4x=16
x=4
∴xy=4×2
=8
2×4+3y=14
8+3y=14
3y=6
y=2
Answered by
0
Answer:
1) x/3 + y/2=4
x + y= 4x3x2 (∵ all constants have to be on one side, and the opposite of
division is multiplication)
x + y = 24
2) 2x/3 - y/4=3
2x-y= 3×3×4 (∵ Constants have to be on one side)
x - y= 36÷2
x - y= 18
hope it helped :)
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