Question

Solve the equation
x square -2x-3=0 by completing the square​

Answer 1

Step-by-step explanation:

x2-2x-3

x2-3x+1x-3

x(x-3)+1(x-3)

(x+1)(x-3)

x+1=0 or x-3=0

x=-1 or x=3

Sorry bro it is factorization method If you want this then you can or you can ignore it . I don't read that you want completing square method

Answer 2

✨Given ÷

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x²-2x-3=0

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✨Method used

By completing square method

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✨Formula used ...

$\color{red} \boxed{d = {b}^{2} - 4 \times a \times c } \\ \\ \color{blue} \boxed{x = \frac{ - b + - \sqrt{d} }{2a} }$

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✨ Solution...

${x}^{2} - 2x - 3 = 0 \\ \\ a = > 1 \\ b = > - 2 \\ c = > - 3 \\ \\ by \: completing \: square \\ \\ d = {b}^{2} - 4ac \\ \\ d = > { (- 2)}^{2} - 4 \times 1 \times - 3 \\ \\ d = > 4 + 12 \\ \\ \color{red} \boxed {d = 16}$

$x = \frac{ - b + - \sqrt{d} }{2a} \\ \\ x = > \frac{ - b + \sqrt{d} }{2a} \: \: \: \: \: \: x = > \frac{ - b - \sqrt{d} }{ 2a} \\ \\ x = > \frac{ - 2 + \sqrt{16} }{2 \times 1} \: \: \: \: \: \: x = > \frac{ - 2 - \sqrt{16} }{2 \times 1} \\ \\ x = > \frac{ - 2 + 4}{2} \: \: \: \: \: x = > \frac{ - 2 - 4}{2} \\ \\ x = > \frac{2}{2} \: \: \: \: x = > \frac{ - 6}{2} \\ \\ x = > 1 \: \: \: \: \: \: x = > - 3$

The nature of roots of x²-2x-3 =0 are 1 and -3....

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Thanks ✨✨✨