Question

Solve the equation x+y/2=4 x+2y=5 in substitution method

Answer 1

Answer:

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[1] 11y = 22

[1] y = 2

// By now we know this much :

x = -6y+15

y = 2

// Use the y value to solve for x

x = -6(2)+15 = 3

Answer 2

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$\bf\underline {given}$

• x+y/2=4
• x+2y=5

$\bf \: 2x + y = 8.......(1) \\ \bf \: x + 2y = 5......(2)$

• Multiply eq(1) by 2

• 4x+2y=16........(3)

• Multiply eq (2) by 1

• x+2y=5........(4)

$\bf \: equating \: \: eq \: \: (3) \: \: and \: \: (4) \\ \sf \: 4x + 2y = 16 \\ \sf \: x \: \: + 2y = 5 \\ \sf \underline {( - ) \: \: \: ( - ) \: \: \: ( - )} \\ \sf \underline{3x \: \: \: \: \: \: \: \: \: \: = 21} \\ \sf \: x = 7 \\ \\ \\ x = 7 \: \: sub \: in \: \: eq(4) \\ \sf \: x + 2y = 5 \\ \sf \: 7 + 2y = 5 \\ \sf \: \: 2y = - 2 \\ \sf \: \: y = - 1$