solve the equation√x²-3x=4x²-12x-3
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i) Given: √(x² - 3x) = 4x² - 12x - 3 = 4(x² - 3x) - 3
ii) Let x² - 3x = y;
So the given one reduces to: √y = 4y - 3
iii) Squaring both sides, y = 16y² + 9 - 24y
Rearranging and simplifying, 16y² - 25y + 9 = 0
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