solve the equation x²+3x+9=0
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x²+3x+9=0
ax²+bx+c=0
:.a=1, b=3,c=9
x=-b±√b²-4ac/2a
x=-3±√9-4×1×9/2
=-3±√-27/2
=-3±3√3×√-1/2
=-3±I 3√3/2
:.x=-3+i3√3/2
=-3-i3√3/2
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