Math, asked by kavya16, 1 year ago

Solve the equation x²+5x-(a²+a-6)=0

kavya16: The question is correct.

ahmedpumpwala: there are two variables...

ahmedpumpwala: how can we solve

kavya16: I got a value of x in terms of a but i am not sure.

Anonymous: what was the value?

kavya16: x= -(a+3) or x= a-2

Anonymous: how?

kavya16: by using quadratic formula or factorisation method

ahmedpumpwala: how eqn can be solved if two variables are present

kavya16: x²+5x-(a²+a-6)=0. => x²+5x-(a²+3a-2a-6)=0. => x²+5x-[a(a+3) -2(a+3)] =0 =>. x²+5x-(a+3) (a-2) =0 =>. x²+[(a+3)-(a-2)] x -(a+3) (a-2) =0 => x²+(a+3)x -(a-2)x -(a+3) (a-2) =0 => x[x+(a+3)] - (a-2) [x+(a+3)] =0 => [x+(a+3)]. [x-(a-2)]=0. =>. x= -(a+3) or x= a-2

Answers

Answered by Prachi12345

This can be like this
hope it will help u

Attachments:

Previous Question

Next Question