Question

Solve the equation x2-(root 3 +1)x+root 3= 0 by the method of completing the square.​

Answer 1

Answer:

x2-(√3 +1)x+√3= 0

Or, x2-√ 3 x-x+√3= 0

or, x(x-√3)-1(x-√3)=0

or, (x-√3) (x-1) =0

now, (x-√3)=0 or, x=√3

or,

(x-1) =0 or, x=1

the solutions are √3 and 1