Question

solve the equation x²+x-12=0​

Answer 1

Answer:

x = 3 and -4

Step-by-step explanation:

x²+x-12 = 0

x² + 4x -3x - 12  = 0

x(x + 4) - 3(x + 4) = 0

(x - 3)(x + 4) = 0

x -3 = 0 ; x + 4 = 0

x = 3    ; x = -4

Answer 2

Hey mate! Here's your answer

Factor it: x2 + x - 12 = 0

This equation is in the ax2 + bx + c form, so c is -12

Since c is negative, you know that the factoring would have one positive x-value and one negative x-value; a positive number times a negative number would be negative.

So now you know that it will be:

(x + __ ) * (x - __ ) = 0

Now find the factors of -12 that will add/subtract to get positive 1 (since your b-value is 1x.) -3 and 4 multiply to get -12, and add to get 1

Therefore, it would be:

(x + 4) * (x - 3) = 0

So x would be the number that makes the value in the parentheses equal to 0.

-4 + 4 = 0 and 3 - 3 = 0

So x = - 4, 3

Hope it is helpful to you