Solve the equation x2x-15x-126=0 by cardon method
Answers
Answer:
Simplifying
x2 + 15x + -126 = 0
Reorder the terms:
-126 + 15x + x2 = 0
Solving
-126 + 15x + x2 = 0
Solving for variable 'x'.
Factor a trinomial.
(-21 + -1x)(6 + -1x) = 0
Subproblem 1
Set the factor '(-21 + -1x)' equal to zero and attempt to solve:
Simplifying
-21 + -1x = 0
Solving
-21 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '21' to each side of the equation.
-21 + 21 + -1x = 0 + 21
Combine like terms: -21 + 21 = 0
0 + -1x = 0 + 21
-1x = 0 + 21
Combine like terms: 0 + 21 = 21
-1x = 21
Divide each side by '-1'.
x = -21
Simplifying
x = -21
Subproblem 2
Set the factor '(6 + -1x)' equal to zero and attempt to solve:
Simplifying
6 + -1x = 0
Solving
6 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-6' to each side of the equation.
6 + -6 + -1x = 0 + -6
Combine like terms: 6 + -6 = 0
0 + -1x = 0 + -6
-1x = 0 + -6
Combine like terms: 0 + -6 = -6
-1x = -6
Divide each side by '-1'.
x = 6
Simplifying
x = 6
Solution
x = {-21, 6}