Solve the equation x³ - 9x² +14x + 24 = 0 if it is given that two of its roots are in the
ratio 3:2.
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Step-by-step explanation:
x³ - 9x² +14x + 24 = 0
Let the roots be 3a 2a and b
Now sum of roots
5a+b =9
Product of roots
6a²b = -24
a²b = -4
b = -4/a²
5a-4/a²=9
5a³ - 9a² -4 = 0
5a³ + a²+2a-10a²-2a -4 = 0
a(5a²+a+2)-2(5a²+a+2) = 0
(a-2)(5a²+a+2)=0
Since
5a²+a+2 >0
a-2=0
a=2
b=-1
Therefore the roots are
6 , 4 and -1
Hope it helps
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