Question

solve the equation x4-26x2+25=0

Answer 1

x^4-26x^2+25=0

x^4-x^2-25x^2+25=0

x^2(x^2-1) -25(x^2-1) =0

(x^2-1) (x^2-25) =0

x^2-1=0

x^2=1

x=1
or

x^2-25=0

x^2=25

x=5

Answer 2

The value of x for the given equation is either +1 or -1.

Given:

$x^{4} - 26x^{2} +25=0$

To find: The value of x

Solution:

         $x^{4} - 26x^{2} +25=0\\or, x^{2} (x^{2} -26+25)=0\\or, x^{2} -26+25=0\\or, x^{2} -1=0\\or, x^{2} =1\\or, x= -1 or +1$

Therefore, the value of x can be either +1 or -1.

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