Math, asked by deojosec2003, 8 months ago

Solve the equation x⁴-8x³+24x²-32x+20=0 if 3+i is a root

Answers

Answered by hcps00
2

STEP

1

:

Equation at the end of step 1

((((x4)-(8•(x3)))+(23•3x2))-32x)+16

STEP

2

:

Equation at the end of step

2

:

((((x4) - 23x3) + (23•3x2)) - 32x) + 16

STEP

3

:

Polynomial Roots Calculator :

3.1 Find roots (zeroes) of : F(x) = x4-8x3+24x2-32x+16

Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 1 and the Trailing Constant is 16.

The factor(s) are:

of the Leading Coefficient : 1

of the Trailing Constant : 1 ,2 ,4 ,8 ,16

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 81.00

-2 1 -2.00 256.00

-4 1 -4.00 1296.00

-8 1 -8.00 10000.00

-16 1 -16.00 104976.00

1 1 1.00 1.00

2 1 2.00 0.00 x-2

4 1 4.00 16.00

8 1 8.00 1296.00

16 1 16.00 38416.00

The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms

In our case this means that

x4-8x3+24x2-32x+16

can be divided with x-2

I hope you are understand my solution

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