Question

Solve the equation z = px+qy+log(pq)​

Answer 1

Answer:

1 Type 2: (Clairaut's type)The equation of the form z = px + 1 0 ... Solve z = px + qy + pqSolution: Given: z = px + qy + pq

Step-by-step explanation:

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Answer 2

SOLUTION

TO DETERMINE

Solve the equation :

z = px + qy + log(pq)

EVALUATION

Here the given equation is

z = px + qy + log(pq)

It is an first order non-linear partial differential equation

This is of Clairaut's form

z = px + qy + f(p,q)

Then the solution is of the form

z = ax + by + f(a, b)

Where a and b are constants

Hence the required solution is

z = ax + by + log(a, b)

Where a and b are constants

FINAL ANSWER

The required solution is

z = ax + by + log(a, b)

Where a and b are constants

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