Question

Solve the equation z2 + 3z – 18 = 0. A. z = –3, z = 6 B. z = 3, z = 6 C. z = –6, z = 3 D. z = –6, z = –3

Answer 1

${\huge {\mathfrak {Answer :-}}}$

We have, z^2 + 3z - 18 = 0

Or, z^2 + 6z - 3z - 18 = 0

Or, z(z + 6) - 3(z + 6) = 0

Or, (z + 6)(z - 3) = 0

Or, z = (- 6),3

➡️ Hence, Option(C)

$<i>$ That's it..

Answer 2

hope you get it

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