Question

. Solve the equations :
(1) 3a + 2 = 11 (ii) 4b + 3 = 5b - 2 (ii) y - 6 = 10
iv) 2a + 7 = 5a - 8 (v) 9 = 10 (vi) 7 - 3 = 4
-ii) 8x - 5 = 2x + 19 (viii) 8b - 4 = 3b + 6 (ix) - 3x + 9 = - 15
Find the​

Answer 1

Answer:

1= 3a=11-2

3a=9

a=3/9

a=3

Answer 2

Answer:

3a+2=11

3a=11-2

3a=9

a= 9/3

a=3

4b+3=5b-2

5b-4b=3+2

b=5

y-6=10

y=10+6

y=16

2a+7=5a-8

5a-2a=8+7

3a=15

a=15/3

a=5

9=10???????

7-3=4???????

8x-5=2x+19

8x-2x=19+5

6x=24

x=24/6

x=4

8b-4=3b+6

8b-3b=6+4

5b=10

b=10/5

b=2

-3x+9=-15

-3x=-15-9

-3x=-24

x=-24/-3

x=3

Step-by-step explanation:

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