Question

solve the equations:
1. 7y/10=14
2. 12y/55=24 ​

Answer 1

$\sf{1)\:{\dfrac{7y}{10}}\:=\:14}$

$⟹\sf{7y\:=\:14\:×\:10}$

$⟹\sf{7y\:=\:140}$

$⟹\sf{y\:=\:{\dfrac{140}{7}}}$

$⟹\sf{y\:=\:20}$

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$\sf{2)\:{\dfrac{12y}{55}}\:=\:24}$

$⟹\sf{12y\:=\:24\:×\:55}$

$⟹\sf{12y\:=\:1320}$

$⟹\sf{y\:=\:{\dfrac{1320}{12}}}$

$⟹\sf{y\:=\:110}$

step by step explaination :

Taking the denominator to the right hand side.

i. e. $\sf({\dfrac{7y}{10}}\:=\:14)\:=$ $\sf({7y\:=\:14\:×\:10})$

Multiplying both.

$\sf{(7y\:=\:14\:×\:10)}\:=\:$$\sf({7y\:=\:140)}$

Taking number to right hand side.

$\sf{(7y\:=\:140)}\:=\:$$\sf{(y\:=\:{\dfrac{140}{7}}})$

Cancelling, we get,

$\sf{(y\:=\:{\dfrac{1320}{12}}})\:=\:$

$\sf({y\:=\:110})$

Answer 2

Answer:

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