Math, asked by lalansinghsingh57, 6 months ago

Solve the equations :


2x/3 + y = 16
x + y/4 =14.


please


solve


it

was



very



urgent



for



me



please




solve




it.......


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Answers

Answered by nadiaannthomas
5

Step-by-step explanation:

so first you want to make the whole equation without a denominator or make the denominator into 1. so multiply the first equation with 3 and the other with 4. you would get 2 equations

2x + 3y = 16*3

4x + y = 14*4

do the calculations on your own ik this is your homework

then you solve using elimination method

2x + 3y = 16*3 ) * 2

4x + y = 14*4

subtract the 2nd equation by the first

and u will get the answers

Answered by tulikarani387
2

Answer:

x=12&y=8

2x/3+y=16 --1

x+y/4=14 --2

let's take equation 1

2x/3+y=16

x=48-3y/2 --3

Substitute in eq 2

x+y/4=14

(48-3y/2) +y/4=14

(48-3y/2)=14-y/4

48-3y/2= 56-y/4

4(48-3y) =2(56-y)

192-12y=112-2y

192-112=-2y+12y

80=10y

y=8

Now, substitute value of y in eq 3

x=48-3y/2

x =48-3*8/2

x =12

hope it helps you...

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