Solve the equations 2x-3y = 0 and 3x - 2y = 5 for x and y
Answers
Answered by
7
Answer:
Step-by-step explanation:
2x-3y=0_eq1
3x-2y=5_eq2
Multiplying 2 in eq 1 and 3in eq 2
So,2(2x-3y)=0×2
4x-6y=0_eq3
And 3(3x-2y)=3×5
9x-6y=15_eq4
Now,subtracting eq3 from eq4
9x-6y-(4x-6y)=15-0
9x-6y-4x+6y=15
9x-4x=15
5x=15
x=15/5
x=3
Now,putting the venue of x=3 in eq1
(2×3)-3y=0
6-3y=0
3y=6
y=6/3
y=2
Therefore x=3 and y=2.
Similar questions