solve the equations 2x+3y+z=9,x+2y+3z=6,3x+y+2z=8
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GIVEN :
The equations are 2x+3y+z=9, x+2y+3z=6, 3x+y+2z=8
TO FIND :
The values of x, y, and z in the given equations.
SOLUTION :
Given that the equations are
Now solving the equations (1) ,(2) and (3) by using Elimination method.
Multiply the equation (1) into 3
Now subtracting (4) by (2),
6x+9y+3z=27
x+2y+3z=6
(-)_(-)_(-)_(-)___
_______________
Multiply the equation (1) into 2
Now subtracting (6) by (3),
4x+6y+2z=18
3x+y+2z=8
(-)_(-)_(-)_(-)___
_______________
Now multiply the equation (7) into 5 we get,
Subtracting the equations (5) and (8)
5x+7y=21
5x+25y=50
(-)_(-)__(-)____
-18y=-29
∴ ![y=\frac{29}{18} y=\frac{29}{18}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B29%7D%7B18%7D)
Substitute the value of y in equation (5) we get
∴ ![x=\frac{35}{18} x=\frac{35}{18}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B35%7D%7B18%7D)
Substitute the values of x and y in equation (1) we get
∴ ![z=\frac{5}{18} z=\frac{5}{18}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B5%7D%7B18%7D)
∴ the values of x , y and z are
respectively.
∴
,
and
.
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Step-by-step explanation:
say these answer in rank method
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