Question

solve the equations 2x_y+3z=8, _x+2y+z=4, 3x+y_4z by using gauss jordan method​

Answer 1

Answer:

Step-by-step explanation:

$\left[\begin{array}{cccc}2&1&3&8\\1&2&1&4\\3&1&4&0\end{array}\right]\\ \\R_1->R_1-R_2\\\\\left[\begin{array}{cccc}1&-1&2&4\\1&2&1&4\\3&1&4&0\end{array}\right]\\\\R_2->R_2-R_1\\R_3->R_3-3R_1\\\\\left[\begin{array}{cccc}1&-1&2&4\\0&3&-1&0\\0&4&-2&-12\end{array}\right]\\\\R_2->R_2-R_3\\\\\left[\begin{array}{cccc}1&-1&2&4\\0&-1&1&12\\0&4&-2&-12\end{array}\right]\\\\R_1->R_1-R_2\\R_3->R_3+4R_2\\\\\left[\begin{array}{cccc}1&0&1&-8\\0&-1&1&12\\0&0&2&36\end{array}\right]\\\\R_2->(-1)R_2\\\\R_3->\frac{1}{2}R_3$$\left[\begin{array}{cccc}1&0&1&-8\\0&1&-1&-12\\0&0&1&18\end{array}\right]\\\\R_1->R_1-R_3\\R_2->R_2+R_1\\\\\left[\begin{array}{cccc}1&0&0&-26\\0&1&0&6\\0&0&1&18\end{array}\right]\\\\Therefore\; BY \;GAUSS-JORDAN\; Method\\x=-26\\y=6\\z=18$

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