Question

solve the equations 6x^4-13x^3-35x^2-x+3=0given that 2-√3is a root​

Answer 1

Answer:

Since 2−

3

is a root, we know that 2+

3

is also a root, and corresponding to this pair of roots we have the quadratic factor x

2

−4x+1.

Also 6x

4

−13x

3

−35x

2

−x+3=(x

2

−4x+1)(6x

2

+11x+3);

Hence the other roots are obtained from

6x

2

+11x+3=0, or (3x+1)(2x+3)=0;

Thus, the roots are −

3

1

,−

2

3

,2+

3

,2−

3

.

Answer 2

Answer:

x=−23 =−1.500

x=− 31 =−0.333

x= 24− 12 =2− 3 =0.268

x= 24+ 12 =2+ 3 =3.732

Step-by-step explanation: