Question

solve the equations -a+b=1,3a +2b+d=0,-2a-b-d=0

Answer 1

-a+b=1
b=1+a------------(1)



3a +2b+d=0
3a+2(1+a)+d=0
3a + 2+2a+d = 0
5a + 2 + d=0
d = -2-5a--------(2)

-2a-b-d = 0
-2a-(1+a)-(-2-5a) = 0
-2a -1-a+2+5a = 0
2a+1=0
a=-1/2


b= 1+a
b= 1+-1/2
b= 1/2


d= -2-5a
d= -2-5(-1/2)
d= -2+5/2
d= -4+5/2
d= 1/2

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