Question

solve the equations to find the values of A, B and C
A+C=1
3A+B+2C=1
2A+2B+C=1
( the anwers are the values of a,b,c as -2, 1, 3 respectively)
i want the proper explaination of how you have solve. if possible please provide with a image of the solution.
(most helpful will be marked brainliest)
THANKYOU!​

Answer 1

Answer:

-2,1,3

Step-by-step explanation:

A+C=1

3A+B+2C=1    ===>    A+A+A+B+C+C=1    ===>  A+C+A+C+A+B=1 ===>1+1+A+B=1 ===>A+B=-1

A+C+A+B=1+(-1)

2A+B+C=0

2A+2B+C=1 ===>   A+A+B+B+C=1 ===> 2A+B+C+B=1 ===> 0+B=1 ===>B=1

Sub B=1 in A+B=-1 then A=-2

Sub A=-2 in A+C=1 then C=3

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Answer 2

Answer:

i) A+C =1

-2+3=1

ii) 3A+B+2C =1

3×(-2)+1+2+3

Or, -6+1+6 =1

iii) 2A+2B+C =1

Or, 2×(-2)+ 2×1 +3

or, -4+2+3

or, -2+3=1

So, A= -2, B= 1, C= 3