Question

solve the equatuon 5x^4-22x^2+8=0​

Answer 1

Answer:

= (5x^2-2)(x-2)(x-2)

Step-by-step explanation:

$= 5x^4 - 22x^2 + 8\\= 5x^4 - 20x^2 - 2x^2 + 8\\= 5x^2(x^2 - 4) -2(x^2-4)\\=(5x^2-2) (x^2 - 4)\\= (5x^2-2)(x-2)(x-2)$