Question

Solve the exact differential equation (y^4+4x^3 y+3x)dx+(x^4+4xy^3+y+1)dy=0.

Answer 1

Answer:

sorry I want some point s

Answer 2

Answer:

If you multiply through by x^2 you can turn this into an exact differential equation.

(4x^3 y^3 - 9 x^2 y^2 + 4x^3 y^2) dx + (3x^4y^2 - 6x^3y + 2x^4 y) dy

d/dy (4x^3 y^3 - 9 x^2 y^2 + 4x^3 y^2) = 12 x^3 y^2 - 18x^2 y + 8 x^3 y

d/dx (3x^4 y^2 - 6 x^3 y + 2 x^4 y) = 12 x^3 y^2 - 18x^2 y + 8 x^3 y